4[3-(-8x-7)]=64x+68

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Solution for 4[3-(-8x-7)]=64x+68 equation:


Simplifying
4[3 + -1(-8x + -7)] = 64x + 68

Reorder the terms:
4[3 + -1(-7 + -8x)] = 64x + 68
4[3 + (-7 * -1 + -8x * -1)] = 64x + 68
4[3 + (7 + 8x)] = 64x + 68

Combine like terms: 3 + 7 = 10
4[10 + 8x] = 64x + 68
[10 * 4 + 8x * 4] = 64x + 68
[40 + 32x] = 64x + 68

Reorder the terms:
40 + 32x = 68 + 64x

Solving
40 + 32x = 68 + 64x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-64x' to each side of the equation.
40 + 32x + -64x = 68 + 64x + -64x

Combine like terms: 32x + -64x = -32x
40 + -32x = 68 + 64x + -64x

Combine like terms: 64x + -64x = 0
40 + -32x = 68 + 0
40 + -32x = 68

Add '-40' to each side of the equation.
40 + -40 + -32x = 68 + -40

Combine like terms: 40 + -40 = 0
0 + -32x = 68 + -40
-32x = 68 + -40

Combine like terms: 68 + -40 = 28
-32x = 28

Divide each side by '-32'.
x = -0.875

Simplifying
x = -0.875

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